But what if $V_{in}$ is a time varying function, like $$V_{in}(t) = \sin{\omega t}$$
Now, we replace the lower resistor, $R_2$ with a capacitor.
And what happens if instead we feed a time varying signal to the circuit.
It all depends on the ratio of $t/\tau$.
Cutoff Frequency $$f_c = \frac{1}{2 \pi R C}$$
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